Askier of mass 65.0 is pulled up a snow-covered slope at constant speed by a tow rope that is parallel to the ground. the ground slopes upward at a constant angle of 26.0 above the horizontal and you can ignore friction. calculate the tension in the tow rope.

 T = 279.24 N

Explanation:

given,

mass of skier = 65 Kg

angle made with horizontal = 26°

tension in the tow rope = ?

tension along horizontal

T = m g  sin θ

T = 65 x 9.8 x sin 26°

 T = 279.24 N

Hence, tension in the tow rope is equal to  T = 279.24 N

the working equation for the angular size is the product of the physical size and 360 degrees divided by the product of two pi and distance from earth. the minimum size would be 0.559 degrees while the maximum size would be 0.49 degrees.