Acowboy at a dude ranch fills a horse trough that is 1.53 m long, 61 cm wide, and 42 cm deep. he uses a 2.0-cm-diameter hose from which water emerges at 1.66 m/s. how long does it take him to fill the trough?

It takes him 751.39 seconds to fill the trough

Explanation:

The flow rate  = Velocity of the hose × cross sectional area of the hose.

Q = V×A Equation 1

Where Q = flow rate, V = velocity, A = cross sectional area.

Given: V = 1.66 m/s,

A =πd²/4, Where d = 2.00 cm = 0.02 m.

Therefore, A =  3.143(0.02)²/4 = 0.0003143 m²

Substituting these values into equation 1

Q = 1.66×0.0003143

Q = 0.0005217 m³/s.

Time taken to fill the trough = Volume of the trough/flow rate.

t = V/Q Equation 2.

Where V = volume of the trough, Q = flow rate.

Given: Q = 0.0005217 m³/s, V = length×width×height = l×w×h, l = 1.53 m, w = 61 cm = 0.61 m, h = 42 cm = 0.42 m.

V = 1.53×0.61×0.42 = 0.392 cm³

Substituting these value into equation 2,

t = 0.392/0.0005217

t = 751.39 seconds.

Thus it takes him 751.39 seconds to fill the trough

into the screen

explanation:

the wind is hitting the car into the screen

most voltage drop calculators want the distance between the source and destination. then internally, they double it so both the source and return wires are calculated. but you need to know which distance the calculator uses so you're not half of what you should be or double what you should be.

most circuit breakers will not take a #6 directly, so the electrician will have to splice on a smaller pigtail. you also have to upsize the grounding wire when you upsized the ungrounded (hot) wire (see note in 250.122). this will preclude using most cable assemblies, as a cable with #6 copper will most likely only have a #10 grounding conductor. you need a #6 grounding conductor if the circuit is 20a. a #8 cable is no better, as it will have a #10 grounding conductor too. but most 20a breakers will take a #8 directly.

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