8,000,000 kg of water are at the verge of dropping over niagara falls to the rocks 50.0 m below. what is the change in gravitational potential energy as the water splashes on the rocks below? ( calculate gpe final and gpe initial and then find the difference)

i will very much appreciate it you!

The Change in the Gravitational Potential Energy as the water splashes out on the rocks below is 3.92 * 10^9 J.

Explanation:

If an object possess energy  because of its position in a gravitational field is called as Gravitational Potential Energy.The formula for the Gravitational Potential Energy is given by,

                                        GPE = mgh

where m represents the mass in kilograms,

            g represents acceleration due to gravity (9.8 m/s^2 in Earth)

            h is the height in meters.

mass = 8,000,000 kg, g = 9.8 m/s^2,   initial height = 0

Initial GPE = 0

Final height = 50.0 m.

Final GPE = 8,000,000 * 9.8 * 50.0 = 3.92 * 10^9 J.

Change in Gravitational Potential Energy = Final GPE - Initial GPE

                                                                        = (3.92 * 10^9) - 0

                                                                        = 3.92 *10^9 J.

answer: the metamorphic rocks are formed when they are exposed to high pressure and high temperatures. this happens when one of the earth's plates comes in contact with the other plate by traveling in opposite directions, straight into each other or slipping under one another. the friction that is caused by this activity results in   melting of rocks and when it cools they are known as metamorphic rocks. this process needs a controlled amount of pressure and temperature otherwise it may turn into magma.