If a rock climber accidentally drops a 56.0 g piton from a height of 295 m, what would its speed be just before striking the ground? ignore the effects of air resistance.

The speed of the piton before hitting the ground = 76.04 m/s

Explanation:

From the law of conservation of energy,

The kinetic energy of the piton  = potential energy of the piton

Note:Before striking the ground, the potential energy of the piton is converted to kinetic energy, with no energy lost to air resistance.

1/2mv² = mgh Equation 1

Where m = mass of the piton, v = speed of the piton, h = height, g = acceleration due to gravity.

making v the subject of the equation above,

v =√(2gh) Equation 2

Given: h = 295 m, g = 9.8 m/s²

Substituting into equation 2

v = √(2×9.8×295)

v = √5782

v = 76.04 m/s

Thus the speed of the piton before hitting the ground = 76.04 m/s

a solenoid is created by wrapping a l = 90 m long wire around a hollow tube of diameter d = 4.5 cm.   the wire diameter is d = 0.9 mm.   the solenoid wire is then connected to a power supply so that a current of i = 9 a flows through the wire.

randomized variablesl = 90 m

d = 4.5 cm

d = 0.9 mm

i = 9 a                                          

write an expression for the number of turns, n, in the solenoid. you do not need to take into account the diameter of the wire in this calculation.

calculate the number of turns, n, in the solenoid.

write an expression for the length of the solenoid (l2) in terms of the diameter of the hollow tube d.

calculate the length of the solenoid (l2)   in meters.

calculate the magnitude of the magnetic field at the center of the solenoid in teslas.

explanation:

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