Asimple pendulum is mounted in an elevator. what happens to the period of the pendulum (does it increase, decrease, or remain the same) if the elevator

(a) accelerates upward at 5.0 m/s2;
(b) moves upward at a steady 5.0 m/s ;
(c) accelerates downward at 5.0 m/s2;
(d) accelerates downward at 9.8 m/s2

Explanation:

Time period of Simple pendulum is given by

where L=length of Pendulum

g=acceleration due to gravity

(a)When elevator is accelerating upward with

effective g will be g+a=9.8+5

therefore time period will decrease

(b)When elevator is moving upward with 5 m/s

effective g will be g as there is no added acceleration

therefore time period will remain same

(c)When elevator is accelerating downward with

effective g will be g-a=9.8-5

therefore time period will increase

(d)When elevator is accelerating downward with

effective g will be g-9.8=0

therefore time period will become infinite

current and voltage can both be different in different parts of a circuit so it matters where you place the ammeter and voltmete