Atruck has four times the mass of a car and is moving with twice the speed of the car. if kt and kc refer to the kinetic energies of truck and car respectively, it is correct to say that: a) kt = 16kc. b) kt = 4kc. c) kt = kc. d) kt = 2kc.

A) Kt = 16Kc.

Explanation:

Kinetic Energy: This is the energy of a body in motion. The S.I unit of kinetic energy is Joules (J).

Mathematically kinetic energy can be represented as

K = 1/2mv² Equation 1

Where K = kinetic Energy, m = mass of the body, v = velocity of the body.

(i) The kinetic energy (Kc) of thevcar,

Kc = 1/2m₁v₁²

Where m₁ = mass of the car, v₁ = velocity of the car.

Kc = 1/2(m₁v₁)

If the mass of the truck is four times the mass of the car and is moving with twice the speed of the car.

Therefore,

Kt = 1/2(4m₁)(2v₁)²

Kt = 8m₁v₁²

From the above,

Kt/Kc = 4m₁v₁²/(1/2m₁v₁²)

Kt/Kc = 16

Kt = 16Kc

Thus the right option is A) Kt = 16Kc.

because if the tool that you are using is not balanced it there would be false mass.

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