An electric drill starts from rest and undergoes uniform angular acceleration for a period of 0.145 s until it turns at a rate of 2.85 ✕ 10^4 revs/min.
(a) what is the drill's angular acceleration (in rad/s^2)?
(b) what is the angle (in radians) through which the drill rotates during this period?

Answer

given,

time period, t = 0.145 s

angular velocity, ω = 2.85 x 10⁴ rev/ min

using rotational motion equation

Since it starts from rest ,initial angular velocity ωo=0

final angular velocity

α = 15,527 rad/s²

b)

again using equation of rotational motion

    θ = 163.23 rad

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hope this ! ~

1/0.14nm = 10^10/1.4 a lot