Akangaroo can jump over an object 2.50 m high. (a) considering just its vertical motion, calculate its vertical speed when it leaves the ground. (b) how long a time is it in the air?

Explanation:

a) We have equation of motion v² = u² + 2as

Initial velocity, u = ?

Acceleration, a = -9.81 m/s²  

Final velocity, v = 0 m/s  

Displacement, s = 2.50 m

Substituting  

v² = u² + 2as

0² = u² + 2 x -9.81 x 2.50

u = 7 m /s

Vertical speed when it leaves the ground is 7 m/s

b)  We have equation of motion s = ut + 0.5 at²

        Initial velocity, u = 7 m/s

        Acceleration, a = -9.81 m/s²  

        Displacement, s = 0 m   --- Time is calculating for returning to ground    

     Substituting

                      s = ut + 0.5 at²

                      0 = 7 x t + 0.5 x -9.81 x t²

                      t = 1.43 seconds

Kangaroo is in air for 1.43 seconds.

explanation:

earth's surface is mainly heated by the absorption of infrared radiation from the sun.

evaporation occurs because molecules in liquid water are warmed ( usually by the sun) and vibrate quicker, becoming less dense and rise.

condensation occurs because molecules in water vapor are cooled and therefore vibrate more slowly thus becoming more dense and eventually fall to earth.

lines of equal barometric pressure on a weather map are called: isobars : lines of equal temp on a weather map are called: isotherms.​

47r7eudueueueurudueu37373