Arotating wheel has a constant angular acceleration. it has an angular velocity of 5.0 rad/s at time t = 0 s, and 3.0 s later has an angular velocity of 9.0 rad/s. what is the angular displacement of the wheel during the 3.0-s interval?

Explanation:

We have equation of motion v = u + at

     Initial velocity, u = 5 rad/s

     Final velocity, v = 9 rad/s    

     Time, t = 3 s

     Substituting

                      v = u + at  

                      9 = 5 + a x 3

                      a = 1.33 rad/s²

     Angular acceleration is 1.33 rad/s²

Now we have equation of motion v² = u² + 2as

     Initial velocity, u = 5 rad/s

     Final velocity, v = 9 rad/s    

     Angular acceleration = 1.33 rad/s²

Substituting  

v² = u² + 2as

9² = 5² + 2 x 1.33 x s

s = 21 radians

Angular displacement during 3 seconds is 21 rad

unable to answer the rest since your question is incomplete

higher potential

explanation:

because it is in a high speed so it must move into a of high potential