Ahorizontal force of 100 n is used to pull a crate, which weighs 500 n, at constant velocity across a horizontal floor. what is the coefficient of kinetic friction?

The coefficient of kinetic friction is 0.2.

The velocity is constant.

Therefore,

acceleration  = 0 m/s²

Net force = 0

Therefore,

100 - f = ma

100 - f = m × 0

100 - f = 0

f = 100Newton

f = μN

where

N= normal force

μ = coefficient of kinetic friction

100 = 500μ

μ = 100 / 500

μ = 0.2

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0.2

Explanation:

Horizontal force=100N

Weight of crate=500 N

We have to find the coefficient of kinetic friction.

Normal ,N=Weight=500N

Horizontal force,

Where =Horizontal force

N=Normal force

=Coefficient of kinetic friction

Substitute the values in the formula

Hence, the coefficient of kinetic friction =0.2

when earth is in rotational motion around the sun,it displaces from its place.

when a ball is placed on an inclined surface it does both the rotational and circular motion.

explanation:

answer: the rock sample is a sedimentary rock.

explanation:

it is given that:

mass of rock sample, m = 2.7 g

volume of rock sample,

so, density of rock sample will be

since, the density of rock sample is . hence, the rock sample is a sedimentary rock, whose densities varies between .