Racing on a flat track, a 755 kg car going 32m/s rounds a
curve 56m in radius. what is the car's centripetal
acceleration? *

18.29m/s^2

Explanation:

Centripetal acceleration=(velocity)^2÷radius

Centripetal acceleration=(32^2)/56

Centripetal acceleration=(32×32)/56

Centripetal acceleration=1024/56

Centripetal acceleration=18.29m/s^2

the minimum constant speed at which she can catch the train is 2.7 m/s

given:

acceleration = 0.6

time = 4.5 s

to find:

velocity = ?

formula used:

from 1st kinematic equation we get,

v = u + at

u = initial speed of train = 0 m/s

v = final speed of the train

a = acceleration of the train

t = time

solution:

from 1st kinematic equation we get,

v = u + at

u = initial speed of train = 0 m/s

v = final speed of the train

a = acceleration of the train

t = time

v = 0 + (0.6 × 4.5)

v = 2.7 m/s

the minimum constant speed at which she can catch the train is 2.7 m/s

find the surface area of the sphere to the nearest square unit. use a calculator.

a. 254 in.2

b. 64 in.2

c. 127 in.2

d. 1,018 in.2