The electrical force on a 2-coulomb charge is 60 newtons (n). what is the magnitude of the electric field at the place where the charge is located?

Explanation:

The given data is as follows.

            Charge (q) = 2 coulomb,        Force (F) = 60 N

Now, it is known that the relation between electric field, force and charge is as follows.

       Magnitude of electric field (E) =

Hence, putting the given values into the above formula as follows.

              Electric field (E) =

                                         =

                                         = 30 N/C

Thus, we can conclude that the magnitude of the electric field at the place where the charge is located is 30 N/C.

0.863333

86%

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