Suppose you have a balloon with a volume of 0.1 m3 and a temperature of 300 kelvin. you leave the balloon in a car with the windows rolled up and the temperature rises to 315 degrees kelvin. what is the new volume of the balloon?

New Volume=0.105 m³

Explanation:

Given Data

balloon with a volume = 0.1 m³ at temperature of 300 Kelvin

To find

The volume when temperature rises 315 Kelvin

Solution

The ideal gas law is given as:

PV = nRT

Where n is the number of moles

R is the universal gas constant.

V is volume

T is temperature

P is Pressure

For this problem the P, n, R (R = 8.314 J/mol·K) are constant, Volume  and Temperature are directly proportional

As Temperature rises by 5%=300+(300×0.05)=315 Kelvin

Same as for Volume

Volume will increase by 5%=0.1+(0.1×0.05)=0.105 m³  

New Volume=0.105 m³  

(75°f − 32) × 5/9 = 23.889°c

  distance on the y-axis and time on the x-axis.

explanation:

the instantaneous velocity = change in position/time taken

the slope of the graph should give instantaneous velocity.

  slope of a graph = change in value of y -axis / change in values of x -axis

  comparing both the equations

    change in value of y -axis = change in position

  change in values of x -axis = time taken

so position values should be on the y axis and time values should be on the x axis.

distance on the y-axis and time on the x-axis.