Two point-charges exert a 5 n force on each other. what will the force become if the distance between them is increased by a factor of three?

force decreased by a factor of 9

Explanation:

According to Coulomb's law:

where C1 and C2 are the charges of the 2 points. Fc is the charge force and R is the distance between them. Since the distance is squared in the denominator, if R is increased by a factor of 3, the force Fc would be decreased by a factor of times

energy stored in the capacitor= 9.72 x 10⁻⁴ j

explanation:

the energy stored in the capacitor is given by

e= 1/2 c v²

e= energy stored

c= capacitance= 1.5 µc= 1.5 x 10⁻⁶f

v= potential difference=36 v

so energy stored= e= 1/2 (1.5 x 10⁻⁶) (36)²

energy stored= 9.72 x 10⁻⁴j