The driver of a car traveling at 22.8 m/s applies the brakes and undergoes a constant deceleration of 2.95 m/s 2 . how many revolutions does each tire make before the car comes to a stop, assuming that the car does not skid and that the tires have radii of 0.2 m? answer in units of rev.

70 revolutions

Explanation:

We can start by the time it takes for the driver to come from 22.8m/s to full rest:

The tire angular velocity before stopping is:

Also its angular decceleration:

Using the following equation motion we can findout the angle it makes during the deceleration:

where = 0 m/s is the final angular velocity of the car when it stops, = 114rad/s is the initial angular velocity of the car = 14.75 rad/s2 is the deceleration of the can, and is the angular distance traveled, which we care looking for:

or 440/2π = 70 revelutions

0.3x0.21x0.08kg=mass 1 sheet

mass 500 = 500xmass 1

volume pile = 0.3x0.2x0.048

density=mass/volume= 500xmass 1/0.3x0.2x0.048

v patient student

i don't understand. explain it clearly