Physics, 09.01.2020 05:31 anrs14

Afrog in a hemispherical pod finds that he just floatswithout
sinking in a fluid of density 1.25 g/cm3. if the pod has
a radius of3.00 cm and negligible mass, what isthe mass of the
frog?

Answers: 3

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Answer from: Baby010391

The mass of the frog = 70.72 g

Explanation:

From the law of flotation,

Weight of the frog = weight of the fluid displaced

Wₓ = Wₐ Equation 1

Where Wₓ Weight of the frog, Wₐ = weight of the fluid displaced.

But,

Wₓ = mₓg Equation 2

Wₐ = ρVg Equation 3

Where mₓ = mass of frog, V = volume of fluid displaced, ρ = density of fluid, g = acceleration due to gravity.

Substituting both equation 2 and 3 into equation 1

mₓg = ρVg

Equation g from both side of the equation,

mₓ = ρV Equation 4

Given: ρ = 1.25 g/cm³, and V = volume of a hemisphere = 2/3πr³

Where r = radius of the pod = 3.00 cm³, π = 3.143

V = 2/3(3.143)(3)³

V = 2×3.143×9

V = 56.574 cm³

Substituting these values into equation 4,

mₓ = 1.25×56.574

mₓ = 70.7175 g

mₓ ≈ 70.72 g

Thus the mass of the frog = 70.72 g

Answer from: Quest

answer: the correct answer is 1.

explanation: there are various process in which a radioactive nuclei decays:

1) alpha decay: in this process, a heavier nuclei decays into lighter nuclei by releasing alpha particle. the mass number is reduced by 4 units.

$_a^z\textrm{x}\rightarrow _{a-2}^{z-4}+_2^4\alpha$

2) electron capture: in this decay process, a parent nuclei absorbs an electron and gets converted into a neutron. simply, a proton and an electron combines together to form a neutron. mass number does not change in this process.

$_a^z\textrm{x}+_{-1}^0\textrm{e}\rightarrow _{z-1}^a\textrm{y}$

3) gamma ray emission: it is a decay process in which an unstable nuclei gives excess energy by a spontaneous electromagnetic process. this decay releases $\gamma -radiations$ . this process does not change the mass number.

$_a^z\textrm{x}^*\rightarrow _a^z\textrm{x}+_0^0\gamma$

4) positron emission: it is a type of decay process, in which a proton gets converted to neutron and an electron neutrino. this is also known as $\beta ^+$ -decay. in this the mass number remains same.

$_a^z\textrm{x}\rightarrow _{z-1}^a\textrm{y}+_{+1}^0e$

from the above information, we see that only alpha-decay is producing a change in the mass number of the nucleus.

Answer from: Quest

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Afrog in a hemispherical pod finds that he just floatswithout
sinking in a fluid of density 1....