Arope, assumed massless is stretched horizontally between
twosupports that are 3.44 m apart. when an object of weight 3160 n
ishung at the center of the rope, the rope is observed to sag by
35.0cm. what is the tension of the rope?

7900N

Explanation:

35cm = 0.35m

When the object is at the rope center, its position at 3.44 / 2 =1.72m. We can find out the angle that the sagged rope makes with the horizontal

this means the rope makes with the vertical an angel of

90 - 11.5= = 78.5 degree

The tension of the 2 ropes, T, should balance with the object weight

= \frac{3160}{2*0.2} = 7900N[/tex]

i think it’s a. this is because if they measured the mass of something with a mass of 150g, then their final answer would have to be approximately 150g. though all of their answers are almost 150, rosa and tran have the closest answers (or the exact answer) to the accurate one.