Aparticle moves through an xyz coordinate system while a force acts on it. when the particle has the position vector r with arrow = (2.00 m)i hat − (3.00 m)j + (2.00 m)k, the force is f with arrow = fxi hat + (7.00 n)j − (5.80 n)k and the corresponding torque about the origin is vector tau = (3.40 n · m)i hat + (2.80 n · m)j + (0.800 n · m)k. determine fx.