Asimple piping system consisting of a small pipe (diameter 6 cm) connected to a larger pipe (diameter 30 cm) is used to transfer and magnify force from one end to the other. the system is full of water and completely enclosed by two pistons, one on each end. if a force 11.2 n is exerted (additional to the forces already present) on the small piston, then how much additional force is exerted at the larger piston

280N

Explanation:

Pascal's law states that the pressure in a fluid is transmitted across every point in the fluid system.

Hence, the pressure in both tubes must remain same;

So, pressure = F1/A1 = F2/A2

where F1 = initial force on small pipe, A1 = area of small pipe

F2 = force on larger piston, A2 = area of larger piston

Given:

F1 = 11.2N

D1 = diameter of smaller pipe = 6 cm

D2 = diameter of larger piston = 15 cm

A1 = π*(r1)² = π*(6/2)² =π*9 (As radius, r = diameter/2)

A2 = π*(r2)² = π*(30/2)² =π*225

Hence 11.2/π*9 = F2/π*225

solving, we have

F2 = 280N

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the ima (higher than 1m) will be greater than the ima with the height of 1m.