Acustodian is struggling to move a 100. kg desk on a dolly, using a rope. he is pulling on the rope at a 60. ◦ angle. (a) how much force will the custodian need to apply in order to cause the desk to accelerate horizontally at a rate of 1.0 m s 2 ? (b) you suggest that the custodian will have an easier time if he uses a longer rope, which will decrease the angle. if the longer rope results in an angle of 30. ◦ , much force will the custodian need to apply in order to cause the 100. kg desk to accelerate horizontally at 1.0 m s 2 ?

W= fd
where f is an applied force and d is the distance over which it is applied. when a parachuting skydiver is at constant velocity, he is experiencing "terminal velocity", the point at which his acceleration down is canceled out by air resistance. that means that the resisting force of the air is equal to his weight, but in the opposite direction. with this, we can solve for the work done by the force.
w = fd
w = (92.0)(9.81 m/s^2) (325)
w= 2.93 x 10^5 j
the value for work in this case is positive because it is pushing up on the skydiver, who has a downward force of gravity.
therefore the answer is 2.93 x 10^5 j