Astronaut rob leaves earth in a spaceship at a speed of 0.960crelative to an observer onearth. rob's destination is a star system 14.4 light-years away (one light-year is the distance lighttravels in one year). relative to a frame of reference that is fixed with respect to earth, how longdoes it take rob to complete the trip?

To solve this problem we will use the mathematical definition of the light years in metric terms, from there, through the kinematic equations of motion we will find the distance traveled as a function of the speed in proportion to the elapsed time. Therefore we have to

means  Light Year

Then

If we have that

Where,

v = Velocity

x = Displacement

t = Time

We have that

= Speed of light

Therefore will take 14.399 years

when jerome paddle in flowing river towards east the net speed of jerome will increase

so the net speed of jerome will be given as

now the speed of paul will be same as it is given as he is running on the ground

so

so here we can say since the speed of jerome is more so he will win the race

now as we know the distance so the time difference is given as

so jerome will reach first and the time difference will be 203.55 s or 3.4 min