In lab, your instructor generates a standing wave using a thin string of length l = 1.65 m fixed at both ends. you are told that the standing wave is produced by the superposition of traveling and reflected waves, where the incident traveling waves propagate in the +x direction with an amplitude a = 2.45 mm and a speed vx = 10.5 m/s . the first antinode of the standing wave is a distance of x = 27.5 cm from the left end of the string, while a light bead is placed a distance of 13.8 cm to the right of the first antinode. what is the maximum transverse speed vy of the bead? make sure to use consistent distance units in your calculations.

given that the distance from the left end of the string to the first antinode is 27.5 cm , calculate the wavelength of the standing wave on the string. remember to convert all measurements into units of meters before performing this calculation.

On the standing waves on a string, the first antinode is one-fourth of a wavelength away from the end. This means

This means that the relation between the wavelength and the length of the string is

By definition, this standing wave is at the third harmonic, n = 3.

Furthermore, the standing wave equation is as follows:

The bead is placed on x = 0.138 m. The maximum velocity is where the derivative of the velocity function equals to zero.

For this equation to be equal to zero, sin(59.94t) = 0. So,

This is the time when the velocity is maximum. So, the maximum velocity can be found by plugging this time into the velocity function:

the moon affects the earth gravitation ally, causing certain motions of that body and also producing tides in its ocean and atmosphere. the tidal wave in our atmosphere is, however, far too minute to be an effective cause in any known meteorological phenomenon.

explanation: