As ocean waves approach shore, their velocity decreases. how does a decrease in velocity affect the frequency and wavelength of the waves
entering the shallow water?
a
frequency increases and wavelength decreases
b. frequency decreases and wavelength increases
c. frequency stays the same and wavelength increases
d.
frequency stays the same and wavelength decreases

D .Frequency stays the same and wavelength decreases .

Explanation:

Due to friction between shore and waves ,  the velocity of waves decreases while reaching the shores . As v = fλ, either frequency or wavelength should decrease. As frequency is the property of the source , it will stay constant and wavelength only decreases .

hi there!

out of the two, (b) precision would be more reasonable.   however, both a and b could be pretty reasonable.

-awesomerepublic   : )

scattering of light by tiny particles in air to produce the colors we see on sky, is dependent on the following factors:

(i) wavelength of light

(ii) size of the scattering particle  

(iii) distance traveled by light through the atmosphere.

according to rayleigh's law of scattering, the amount of scattering is inversely proportional to the fourth power of its wavelength. shorter the wavelength, greater is its scattering. hence violet/blue light is scattered more than red.

sun's light is a composite light ( visible light) with wavelengths in the range 400 nm (violet) to 700 nm (red). as sunlight passes through our atmosphere, the molecules of air scatter light according to their wavelengths. during sunrise and sunset, the sun's position is below the horizon. hence light from the sun travels a greater distance in the atmosphere when compared to its position a noon.

as sunlight enters the earth's atmosphere, blue light is scattered away and at the end of its journey in the sky, only red and orange wavelengths remain in the beam.

hence at sunrise and sunset, the sky appears reddish orange.