What are the charge and the charge density on the surface of a conducting sphere of radius 0.15 m whose potantial is 200v?

The charge and the charge density on the surface of a conducting sphere is and respectively.

Explanation:

It is given that,

Radius of the conducting sphere, r = 0.15 m

Potential, V = 200 V

Potential on the surface of sphere is given by :

q is the charge on the sphere

Charge per unit area is called charge density on the surface. it is given by :

So, the charge and the charge density on the surface of a conducting sphere is and respectively. Hence, this is the required solution.

your answer would be fusion

because it says use -2,0,and 2 for x, we can plug those numbers into the equation. y/4=3/4(-2)+2   y/4= -1 1/2 +2 now to get x by itself, we can multiply each side by 4. y=-6+8 which equals y=2 when x=-2. now you can do the same thing with 0 and 2 as x. you get y=8 when x=0 and y=14 when x=2.

x   |   y

-2 |   2

0   |   8

2   |   14