Physics, 31.12.2019 05:31 Dwoods4515
Tom standing on the roof of a tall building of 60m height throws a ball at angle of 45⁰ .the velocity of the ball is 12 m/s when it leaves tom’s hand.
calculate the following:
a-initial velocity in x, and y direction
b- time to reach to its maximum height.
c-maximum height of the ball with respect to the ground.
d- final velocity –magnitude.
e- velocity of the ball at maximum height.
f- acceleration of the ball at maximum height.
g- total time in the air.
h- distance between the landing spot and the base of the building.
Answers: 2
Physics, 21.06.2019 23:20, lailabirdiemae
Initially, a particle is moving at 5.33 m/s at an angle of 37.9° above the horizontal. two seconds later, its velocity is 6.11 m/s at an angle of 54.2° below the horizontal. what was the particle's average acceleration during these 2.00 seconds in the x-direction (enter first) and the y-direction?
Answers: 1
Tom standing on the roof of a tall building of 60m height throws a ball at angle of 45⁰ .the velocit...
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