Aworker pushes a crate horizontally across a warehouse floor with a force of 245 n at an angle of 55 degrees below the horizontal.
how much of the worker’s force is not used to move the crate?

a. 200.69 n
b. 419.95 n
c. 357.71 n
d. 191.32 n

The worker’s force is 200.69 N.

(a) is correct option.

Explanation:

Given that,

Force = 245 N

Angle = 55°

According to component of force

Horizontal component of force is in direction of displacement which is used to move the crate.

Vertical component of force is not used to move the crate.

We need to calculate the worker’s force which is not used to move the crate

Using y- component of force

Put the value into the formula

Hence, The worker’s force is 200.69 N.

answer: the rock sample is a sedimentary rock.

explanation:

it is given that:

mass of rock sample, m = 2.7 g

volume of rock sample,

so, density of rock sample will be

since, the density of rock sample is . hence, the rock sample is a sedimentary rock, whose densities varies between .

acceleration = (change in speed) / (time for the change)

change in speed = (20-120)= -100 m/s.

1.5 min = 90 sec

acceleration = -100/90 = -1.11 m/s^2.

we don't care about the 150kg or the 2,500 meters. they don't make any difference.

read more on -