Atest charge of +2 μc is placed halfway between a charge of +6 μc and another of +4 μc separated by 10 cm. (a) what is the magnitude of the force on the test charge? (b) what is the direction of this force (away from or toward the +6 μc charge)?

ᵃ. Fₙ= 1.424 x 10¹³ μN

ᵇ. away from the +6 charge

Explanation:

PART A

Using Coulomb's law FOR CHARGES +2 AND +4

F= (Q . q)÷4(3.142)ε(5/100)²

F= 2.848 x 10¹³ μN

for charges of 2 and 6

F₂=(Q . q)÷4(3.142)ε(5/100)

F₂= 4.272 x 10¹³ μN

NET FORCE IS EQUAL TO THE SUM OF ALL THE FORCES ACTING AT A POINT.

FORCE IS A VECTOR QUANTITY, THEREFORE, WE ASSIGN A NEGATIVE SIGN TO ONE OF THE FORCES, as both of them are acting in opposite directions while repelling the +2.

Fₙ= F-F₂

Fₙ= 4.272 x 10¹³ - 2.848 x 10¹³

Fₙ= 1.424 x 10¹³ μN

PART B

The force caused by the +6 charge is twice as much as the one caused by the +4 charge on the same +2 charge, therefore the repulsion caused by the greater charge is greater and has an effect of pushing the +2 charge away from it. However there is also a force of repulsion by the +4 charge which is NOT AS STRONG as compared to the +6 charge, therefore it is less likely to push away the +2 charge

the order for strong to weak forces such as

strong nuclear force → electromegnetic force → weak nuclear force → gravitational force

the fundamental forces are those forces that act between to objects or element to make interactions. there are four types of fundamental forces such as strong and weak nuclear forces (due to protons and electrons), electromagnetic force (due to the motion of electrons) and gravitational force (due to orbital movement of the planet). if these forces are arranged on the basis of their maximum strength then the order is

strong nuclear force → electromegnetic force → weak nuclear force → gravitational force

one person pulls 90n one way and the other has 100n pulling the other way.

so the net force = 90 - 100 = -10n,

or the ans can be 10n if the picture shows -90n and 100n instead.