Aconductor of length 2m carrying a 1.5a current experiences a force of 2.2 n. what is the magnitude of the magnetic field that acts perpendicular to the flow of current in the conductor?

Magnetic field, B = 0.74 T

Explanation:

It is given that,

Length of the conductor, L = 2 m

Current in conductor, I = 1.5 A

Magnetic force, F = 2.2 N

We need to find the magnitude of the magnetic field that acts perpendicular to the flow of current in the conductor. It is given by :

B = 0.74 T

So, the magnitude of magnetic field will be 0.74 T. Hence, this is the required solution.

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