Abaseball with mass 0.145 kg is moving in the+y direction with a speed of 2.10m/s, and a tennis ball with mass 0.0570 kg is moving in the-y direction with a speed of 8.80m/s. what is the magnitude of the total momentum of the systemconsisting of the two balls? what is the direction of the total momentum of thesystem?

a. +x direction
b. +ydirection
c. -x direction
d. -y direction

d. -y direction

Explanation:

Given that

m₁=0.145 kg, u₁=2.1 j m/s

m₂= 0.0570 kg ,  u₂ = -8.8 j m/s

We know that linear momentum is the product of mass and velocity

P= Mass x velocity

Therefore the total linear momentum P

P= m₁u₁+ m₂u₂

Now by putting the values

P = 0.145 x ( 2.1 j) + 0.057 ( - 8.8 j)  kg.m/s

P =0.3045 j - 0.5016 j   kg.m/s

P=  - 0.1971 j kg.m/s

P= 0.1971 (- j) kg.m/s

So we can say that the direction of the liner momentum of the system will be in the negative y -direction.

d. -y direction

e

explanation:

there is no change in the electric potential energy as it is in rest on both conditions.

the old price per ounce is c/4.

the new price per ounce is c/3.6.

the ratio of the old price to the new one is

(c/4)/(c/3.6) = (c/c)×(3.6/4) = 0.9 . . = 9/10 . . "nine tenths" in either form