Calculate the average drift speed of electrons traveling through a copper wire with a crosssectional area of 80 mm2 when carrying a current of 30 a (values similar to those for the electric wire to your study lamp). assume one electron per atom of copper contributes to the current. the atomic mass of copper is 63.5 g/mol and its density is 8.93 g/cm3 . avogadro’s number is 6.022 × 1023 and the fundamental charge is 1.602 × 10−19 c. answer in units of m/s.

The correct answer is

Explanation:

The formula for the electron drift speed is given as follows,

where n is the number of of electrons per unit m³, q is the charge on an electron and A is the cross-sectional area of the copper wire and I is the current. We see that we already have A , q and I. The only thing left to calculate is the electron density n that is the number of electrons per unit volume.

Using the information provided in the question we can see that the number of moles of copper atoms in a cm³ of volume of the conductor is . Converting this number to m³ using very elementary unit conversion we get . If we multiply this number by the Avagardo number which is the number of atoms per mol of any gas , we get the number of atoms per m³ which in this case is equal to the number of electron per m³ because one electron per atom of copper contribute to the current. So we get,

if we convert the area from mm³ to m³ we get .So now that we have n, we plug in all the values of A ,I ,q and n into the main equation to obtain,

which is our final answer.

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explanation:

i just did an experiment like this in my science class. also the answer is yes, it will get separated because they are two opposites meaning if they are opposite they can not attract.

hope this .!