Aprojectile is launched horizontally off a cliff. if the projectile is launched with more velocity, the time it spends in the air will

If the projectile is launched horizontally the time it remains in the air will remain constant even if we increase the horizontal velocity.

Explanation:

The vertical displacement will be the same irrespective of the horizontal velocity assuming the projectile is launched from same height. The formula for vertical displacement is given by:

where, y = vertical displacement, t = time,

g = acceleration due to gravity,

= Initial vertical velocity

Since, projectile is launched horizontally, therefore

so the equation becomes

The above equation shows that time spend in air is not dependent on horizontal launched velocity as there is no horizontal velocity in the formula therefore the time in air will remain constant even if we increase the horizontal velocity.

  the grams     of oxygen gas   that can be produced     is 20.6   grams of o₂

calculation

2liclo₃ →   2 licl + 3 o₂

step 1:   find the moles of liclo₃

moles = mass÷ molar mass

from periodic table the molar mass of liclo₃ =6.9 +35.5   +(16 x3) =90.4 g/mol

moles=38.7 g÷90.4 g/mol=0.4281   moles

step 2:   use the   mole ratio   to calculate the moles of o2

from equation above, liclo₃: o₂   is 2: 3  

therefore the moles of   o₂=0.4281 moles x3/2 =0.6422   moles

step 3: find mass   of o₂

mass= moles x molar mass

from periodic table the   molar mass of   o₂ = 16 x2= 32 g/mol

mass=0.6422   moles   x   32 g/mol = 20.6 grams of o₂

answer would be letter choice (a),   a ball resting on a shelf. would be another example of potential energy   >   stored energy > not moving.

a ball spinning on a finger   >   kinetic energy > moving energy

a ball rolling on the ground   >   kinetic energy   > moving energy

a   ball flying through the air   > kinetic energy   >   moving energy

hope that                                         : )