A95 n force exerted at the end of a 0.50 m long torque wrench gives rise to a torque of 15 n · m. what is the angle (assumed to be less than 90°) between the wrench handle and the direction of the applied force?

angle = 18.40 degree

Explanation:

given data

force = 95 N

distance = 0.50 m

torque = 15 N · m

to find out

angle between the wrench handle and the direction of the applied force

solution

we will apply here torque equation that is express as

torque =  distance × force × sin(θ)   1

put here value we will get angle that is

15 = 0.50 × 95 × sin(θ)

sin(θ) = 0.315789

θ = 18.40 degree

18.4°

Explanation:

Force, F = 95 N

Torque, τ = 15 Nm

length, r = 0.5 m

τ = r F Sinθ

where, θ be the angle between distance vector and force vector

So, 15 = 0.5 x 95 x Sinθ

Sin θ = 0.3159

θ = 18.4°

Thus, the angle is 18.4°.

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the order for strong to weak forces such as

strong nuclear force → electromegnetic force → weak nuclear force → gravitational force

the fundamental forces are those forces that act between to objects or element to make interactions. there are four types of fundamental forces such as strong and weak nuclear forces (due to protons and electrons), electromagnetic force (due to the motion of electrons) and gravitational force (due to orbital movement of the planet). if these forces are arranged on the basis of their maximum strength then the order is

strong nuclear force → electromegnetic force → weak nuclear force → gravitational force