A0.140 kg baseball is thrown horizontally with a velocity of 28.9 m/s. it is struck with a constant horizontal force that lasts for 1.85 ms, which results in a velocity of 37.0 m/s in the opposite direction. what was the magnitude of the horizontal force? a. 0.613 knb. 0.613 kn c. 2.19 kn d. 2.80 kn

To solve this problem, we will express the Force according to Newton's second Law, and acceleration, such as the change of velocity in the body by a certain distance, therefore,

The magnitude of the force is given as

F = ma

Where,

m = mass

a = Acceleration

That can be expressed as,

Replacing with our values we have

F = 0.140kg * (\frac{37+28.9}{1.85*10^{-3}})

F = 4987.03N

F= 4.9kN

Therefore the magnitude of the horizontal force is 4.9kN

answer: 2×10^-2kg

explanation: density= mass per volume

vol=mass/density

converting to s.i units we have;

3÷1000kg = 0.003

1.5÷100m = 0.15

0.003/0.15 = 0.02kg

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