Ablock of mass, m = 10 kg, starts at the top of a frictionless track which forms a quarter circle of radius r = 10 m. it is given an initial downward velocity of vi = 10 m/s. what is its velocity at the bottom of the track?

v=17.32 m/s

Explanation:

Given that

m= 10 kg

R= 10 m

Initial speed ,u= 10 m/s

lets take final speed at the bottom = v m/s

As we know that

Work done by all the forces = Change in the kinetic energy

Now by putting the values

Take g= 10 m/s²

v=17.32 m/s

The speed of the car at bottom will be 17.32 m/s

which three statements are true about all alloys?

mass and volume are the answers you are looking for