Awater tank is filled to a depth of 10 m, and the bottom of the tank is 20 m above ground. a water-filled hose that is 2.0 cm in diameter extends from the bottom of the tank to the ground, but no water is flowing in this hose. the water pressure at ground level in the hose is closest to the density of water is 1000 kg/m3 .

3.95 x 10^5 Pa

Explanation:

total height, h = 10 m + 20 m = 30 m

density of water, d = 1000 kg/m^3

Atmospheric pressure, Po = 1.01 x 10^5 Pa

Pressure, P = Po + h d g

P = 1.01 x 10^5 + 30 x 1000 x 9.8

P = (1.01 + 2.94) x 10^5

P = 3.95 x 10^5 Pa

Thus, the total pressure at the ground is 3.95 x 10^5 Pa.

3.95 x 10⁵ Pa

Explanation:

given,

depth of water tank = 10 m

bottom tank height = 20 m

density of water = 1000 Kg/m³

diameter of hose = 2 cm

Pressure at ground level = ?

net head of water from the ground

H = 20 + 10

H = 30 m

pressure exerted at the ground

P = ρ g h

P = 1000 x 9.8 x 30

P = 2.94 x 10⁵ Pa

atmospheric pressure = 1.01 x 10⁵ Pa

total pressure on the ground

 = atmospheric pressure + pressure due to water tank

 = 1.01 x 10⁵ Pa +  2.94 x 10⁵ Pa

 =  3.95 x 10⁵ Pa

area of focus

the old price per ounce is c/4.

the new price per ounce is c/3.6.

the ratio of the old price to the new one is

(c/4)/(c/3.6) = (c/c)×(3.6/4) = 0.9 . . = 9/10 . . "nine tenths" in either form