Determine the angle of twist of the bar. the bar ia subjected to a torque of t= 571 lb-ft and is of a material of g = 18,431, 356 lb/ in^2. express the results in degrees. the dimensions of the bar are: d1 = 8.1 in d2 = 1.8 in l = 3.1 ft

angle of twist of the bar is 3.32 × degree

Explanation:

given data

torque t = 571 lb-ft = 774.172 Nm

g = 18,431, 356 lb/ in² = 1.27 × Pa

d1 = 8.1 in = 0.205 m

d2 = 1.8 in = 0.045 m

L = 3.1 ft = 0.944 m

to find out

angle of twist of the bar

solution

first we get here polar moment that is express as

polar moment =     ...........1

here do is outer diameter that is 0.205 m and d1 is inner diameter i.e 0.045 m

put here value we get

polar moment =

polar moment = 173.006 ×

now we get here angle that is

angle =   ..............2

here T is torque and L is length and J is polar moment and G is share modulus

put these value in equation 2 we get

angle =

angle = 3.32 × degree

8 meters above the spring

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