Abullet weighing 2.5 g is shot at 350 m/s into a 5 kg wooden block suspended from a 10 m long string. the bullet strikes and is embedded in the block. the block is initially at rest. how high above its initial position does the block swing?

h = 1.56 mm

Explanation:

given,

mass of bullet (m)= 2.5 g

speed of bullet (u)= 350 m/s

mass of wooden plank (M)= 5 Kg

length of string = 10 m

initial velocity of block = 0 m/s

height of block above original position = ?

using conservation of momentum

m u + M u = (m+ M)v

0.0025 x 350 + 0 = (5 +0.0025)v

v = 0.175 m/s

from the conservation of energy

       h = 1.56 mm

when the velocity of a mass on a spring is zero, the acceleration is at a maximum .

a small object of mass 3.66 g and charge -17.6 µc is suspended motionless above the ground when immersed in a uniform electric field perpendicular to the ground. what are the magnitude and direction of the electric field?