Amerry-go-round is rotating at an angular speed of 0.2 radians/s. its motor falls off and it rotates freely. a technician jumps on the edge along the direction of the radius. the angular velocity after he lands is 0.04 radians/s. the moment of inertia of the technician, in (kg m2 ) with respect to the axis of the merry-go-round’s axis of rotation is 5000 kg m2 . what is the moment of inertia of the merry-go-round?

  I₁ =1250  kg.m²

Explanation:

Given that

Angular speed of Merry ,ω₁= 0.2 rad/s

Angular speed of technician ,ω₂= 0.04 rad/s

Moment of the inertia of the technician ,I₂= 5000 kg.m²

Lets assume that

Moment of the inertia of merry with respected to the ground=I₁

There is no any external torque ,that is why angular momentum of the system will be conserve.

Now by conserving angular momentum

I₁ ω₁=(I₁+I₂)ω₂

I₁  x 0.2  = (I₁ +5000 ) x 0.04

I₁ (0.2-0.04) = 5000 x 0.04

I₁ =1250  kg.m²

c. 7/3

step-by-step explanation:

a rational number is like pi- it is a repeating decimal.

a. is -1.8

b. 2.236068

c. 2.3333333333333333333

d.   is 3

i hope that ! =)

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explanation:

physics means: "the branch of science concerned with the nature and properties of matter and energy. the subject matter of physics, distinguished from that of chemistry and biology, includes mechanics, heat, light and other radiation, sound, electricity, magnetism, and the structure of atoms."