The cylinder in the drawing contains 3.00 mol of an ideal gas. by moving the piston, the volume of the gas is reduced to one-fourth its initial value, while the temperature is held constant. how many moles δn of the gas must be allowed to escape through the valve, so that the pressure of the gas does not change?

Δn = 2.25 moles

Explanation:

given,

n₁ = 3 mol

initial volume = V

final volume = V/4

temperature is constant = ?

using ideal gas equation

        n₂ = 0.75 moles

moles of gas allowed to escape

Δn = n₁ - n₂

Δn = 3 - 0.75

Δn = 2.25 moles

moles of gas allowed to escape is equal to Δn = 2.25 moles

because it says use -2,0,and 2 for x, we can plug those numbers into the equation. y/4=3/4(-2)+2   y/4= -1 1/2 +2 now to get x by itself, we can multiply each side by 4. y=-6+8 which equals y=2 when x=-2. now you can do the same thing with 0 and 2 as x. you get y=8 when x=0 and y=14 when x=2.

x   |   y

-2 |   2

0   |   8

2   |   14

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