An 850.0 kg car wants to accelerate from rest to a speed of 18.0 m/s.

it has a useful power output of 47.0 hp (1 hp = 746 w).

neglecting friction.

how much work must the car's engine produce to achieve this increase in speed? don"t use schientific notation when entering your answers. hint: consider the work-kinetic energy theorem.

Explanation:

From Kinetic energy K.E = m*/2

Where mass of the car, m = 850 kg

velocity of the car, v = 18 m/s

Hence K.E =

Also, we can evaluate the given time

time = K.E / Power

=

= 2.87 secs

i think it because equal matrices have equal dimensions, only square matrices can be symmetric. for all indices and . every square diagonal matrix is symmetric, since all off-diagonal elements are zero. in linear algebra, a real symmetric matrix represents a self-adjoint operator over a real inner product space.

c) power lifting, will be your answer.

,

deku ❤