Two parallel wires carry equal currents in the opposite directions. point a is midway between the wires, and b is an equal distance on the other side of the wires. what is the ratio of the magnitude of the magnetic field at point a to that at point b?

Complete Question:(missing part)

The current in the left wire having magnitude is  = 210 A

The Current in the right wire having magnitude is = 10 A

a.

Ratio = B 1/B 2 = 210/10 = 21

Ratio = B 1/B 2 = 210/3 X10 = 7

Explanation:

Ratio of the magnitude of the magnetic field at point A to that at point B =?

The current in the left wire having magnitude is  = 210 A

The Current in the right wire having magnitude is = 10 A

distance between two wires = d

Given that both wires are carrying equal current but in opposite direction therefore

Magnetic field linked with the left wire at point A distance =d/2= according to biot savarts law

Magnetic field linked with the right wire at point B distance =d/2

Net magnetic field added

B net = B 1 + B 2

Ratio = B 1/B 2 = 210/10 = 21

Magnetic field linked to left wire at point B(d+ d/2)

Magnetic field linked to right wire at point B(d+ d/2)

Net magnetic field subtracted

B net = B 1 - B 2

Ratio = B 1/B 2 = 210/3 X10 = 7

the part of the wave he is travelling on is the crest

answer: at 24 february, 2014 the population gets twice of its initial population.

explanation:

since we have given that

the population for alpha city, t years after january 1, 2004 is given as

first we find out the initial population, i.e. t=0,

so, our quadratic equation becomes,

according to question, we have said that if the population has twice its initial population, then it becomes

so, time taken to reach this above mentioned population is given by

now, we know that time can't be negative so, we take t=9.149 years.

hence, at 24 february, 2014 the population gets twice of its initial population.