Afloor jack constists of a small piston of cross-sectional area 2.0 cm2 connected to a large 2 piston of cross-sectional area 100 cm . what is the force on the small piston necessary to lift a 10,000 n car that rests on the large piston

force acting on small piston is 200 N

Explanation:

given data

cross-sectional area a = 2.0 cm² = 2 × m²  

cross-sectional area a = 100 cm²= 100 × =m²  

force f = 10,000 N

to find out

force acting on small piston

solution

we know that here pressure will be equal at all level in horizontal

so pressure at p1 = pressure p2

and pressure =

so  =

put here value we get

 =

solve it we get

force 1 = 200 N

so force acting on small piston is 200 N

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