Along, thin rod parallel to the y-axis is located at x = - 1 cm and carries a uniform positive charge density λ = 1 nc/m . a second long, thin rod parallel to the z-axis is located at x = +1 cm and carries a uniform negative charge density λ = - 1 nc/m. what is the electric field at the origin?

The electric field at origin is 3600 N/C

Solution:

As per the question:

Charge density of rod 1,

Charge density of rod 2,

Now,

To calculate the electric field at origin:

We know that the electric field due to a long rod is given by:

Also,

                 (1)

where

K = electrostatic constant =

R = Distance

= linear charge density

Now,

In case, the charge is positive, the electric field is away from the rod and towards it if the charge is negative.

At x = - 1 cm = - 0.01 m:

Using eqn (1):

    (towards)

Now, at x = 1 cm = 0.01 m :

Using eqn (1):

    (towards)

Now, the total field at the origin is the sum of both the fields:

grav potential energy

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