Physics, 23.12.2019 23:31 GreenHerbz206

Amass hanging from a spring undergoes vertical simple harmonic motion.1) where in the motion is the velocity equal to zero? at the point where the spring is unstretched. at the highest point in the oscillation. at the lowest point in the oscillation.

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Answer from: jonesnr10

At the highest point and at the lowest point the velocity of the mass hung on a spring = 0

Explanation:

Simple Harmonic Motion ( S.H.M) : Simple harmonic motion can be defined as a type of motion were a body vibrates or moves to and fro along a straight line under the influence of a force, so that the acceleration of the body towards a fixed point (equilibrium position) is proportional to its distance or displacement from that point. Examples of bodies undergoing simple harmonic motion are

⇒ The motion of a mass hung on a spring.

⇒ The motion of a simple pendulum

⇒ The motion of a loaded test - tube in a liquid.

Motion of a mass hung on a spring:When a mass is hung to one end spring and other end is firmly clamped to a rigid support.(i)When the mass is in motion, (ii)it pulled down to its lowest point, passes through it equilibrium position (iii) goes to its highest point.

(1) At the lowest and the highest point during the motion of a mass hung a spring, the velocity = 0

(2) At the equilibrium point or unstretched position the velocity is maximum

Answer from: Quest

answer: at 24 february, 2014 the population gets twice of its initial population.

explanation:

since we have given that

the population for alpha city, t years after january 1, 2004 is given as

$p(t)=0.3t^2+6t+80$

first we find out the initial population, i.e. t=0,

so, our quadratic equation becomes,

$p(0)=0+0+80=80$

according to question, we have said that if the population has twice its initial population, then it becomes

$p(t)=2\times 80=160$

so, time taken to reach this above mentioned population is given by

$160=0.3t^2+6t+80\\\\160-80=0.3t^2+6t\\\\80=0.3t^2+6t\\\\0.3t^2+6t-80=0\\\\\text{using quadratic formula ,we get }\\\\t_{1,\: 2}=\frac{-60\pm \sqrt{60^2-4\cdot \: 3\cdot \: 800}}{2\cdot \: 3}\\\\t=-29.14\ and\ t=9.149$

now, we know that time can't be negative so, we take t=9.149 years.

hence, at 24 february, 2014 the population gets twice of its initial population.

Answer from: Quest

the only real purpose of sputnik 1 was to beat the us into space. we were getting close to launching a useful satellite, explorer 1 - which launched on january 31, 1958. the ussr had to beat that, so they launched sputnik 1 on october 4, 19

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Amass hanging from a spring undergoes vertical simple harmonic motion.1) where in the motion is the...