A2510-kg car is coasting up a hill with a 10.0 degree incline at initial speed 20.0 m/s, when a squirrel suddenly darts out into the street ahead of it, and the driver slams on the brakes, causing the car to skid for 20.0 m before the brake is suddenly released and it continues coasting. the coefficient of kinetic friction between the tires and the pavement is 0.500.

Answer

given,

mass of the car = 2510 Kg

angle of inclination = 10°

initial speed = v₁ = 20 m./s

skid length = 20 m

coefficient of friction = 0.5

Using conservation of energy

h = d sin θ

now, calculating the  magnitude of frictional force is equal to

E = F_f d

if the forces acting on an object are unbalanced, the object will accelerate in the direction of the net force on the object.

explanation:

this is best explained by having an understanding of newton's second law, which states that f=ma. you see, when the forces are unbalanced, net force (sum of all forces) is not zero. therefore making it necessary for the object to have an acceleration in the direction of the net force.

force is mass*acceleration.

we have a very small mass: 11.4*0.001 kg

if we want 0.035n of force, we need an acceleration:

0.035 = 11.4*0.001*a

a = 0.035/(11.4*0.001) m/s^2