The small piston of a hydraulic lift has a diameter of 8.0 cm, and its large piston has a diameter of 40cm. the lift raises a load of 15,000n.
a) determine the force that must be applied to the small piston.
b) determine the pressure applied to the fluid in the lift.

Part a)

F = 600 N

Part b)

P = 119366.20 Pascal

Explanation:

Part a)

As we know that by Pascal's law pressure must be transmitted through out the liquid without any change

So pressure at bigger piston = pressure at smaller piston

now by solving above equation we have

Part b)

Pressure applied at fluid is given as

P = 119366.20 Pascal

32: from largest to smallest, this hierarchy includes eons, eras, periods, epochs, and ages.

33: answer is c

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beta is electron from nucleus

something from nucleus has changed, but charge must be same for cons of charge