If a space ship is traveling with a constant acceleration of 75 m/s^2 and travels for three weeks, how far did it travel and what was it's velocity before  it stopped?

The final velocity of the ship is, v = 136050000 m/s

The total distance covered, s = 6.94 x 10¹⁷ m

Explanation:

Given data,

The constant acceleration of the space ship, a = 75 m/s²

The time period of the space ship acceleration is t = 3 weeks

                                                                                   t = 1.814 x 10⁶ s

The initial velocity of the ship is u = 0 m/s

The final velocity of the ship is,

                                    v = u + at

                                       = 0 + 75 (1.814 x 10⁶)

                                       = 136050000 m/s

The distance space ship traveled, can be calculated from the second equation of motion.

                                   s = ut + ½ at²

                                      = 0 + ½ 75 (136050000)²

                                       = 6.94 x 10¹⁷ m

Hence, the total distance covered, s = 6.94 x 10¹⁷ m