Water at 20°c flows by gravity through a smooth pipe from one reservoir to a lower one. the elevation difference is 60 m. the pipe is 360 m long, with a diameter of 12 cm. for the given system a pump is used at night to drive water back to the upper reservoir. if the pump delivers 15,000 w to the water, estimate the flow rate. for water at 20°c, take rho = 998 kg/m3 and μ = 0.001 kg/m-s. round the answer to the nearest whole number.

Flow Rate = 80 m^3 /hours  (Rounded to the nearest whole number)

Explanation:

Given

Calculations

Moody friction loss in the pipe = Hf = (f*L*V^2)/(2*D*g)

The energy equation for this system will be,

Hp = Z + Hf

The other three equations to solve the above equations are:

Re = (rho*V*D)/ μ

Flow Rate, Q = V*(pi/4)*D^2

Power = 15000 W = rho*g*Q*Hp

1/f^0.5 = 2*log ((Re*f^0.5)/2.51)

We can iterate the 5 equations to find f and solve them to find the values of:

Re = 235000

f = 0.015

V = 1.97 m/s

And use them to find the flow rate,

Q = V*(pi/4)*D^2

Q = (1.97)*(pi/4)*(0.12)^2 = 0.022 m^3/s = 80 m^3 /hours

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inverse v=i*r

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