Asimple pendulum with a length of 2.23 m and a mass of 6.74 kg is given an initial speed of 2.06 m/s at its equi- librium position. assume it undergoes simple harmonic motion. determine (a) its period, (b) its total energy, and (c) its maximum angular displacement.

a)   T = 2.997 s

b)   K = 14.3 J

c)   φ = 0.444 rad

Explanation:

a) Determine its period

  The pendulum simple’s period is:

  T = 2π

        Where l: Pendulum’s length

                    g = 9.8 m/s2

  T = 2π

  T = 2.997 s

b) Total energy

  Initially his total energy is kinetic

  K =

  K =

  K = 14.3 J

c) Maximum angular displacement

  φ =

  φ =

  φ = 0.444 rad

double the distance = divide strength by 4

= initial pressure

= final pressure = 2

= initial volume

= final volume = /4

= initial temperature = 20 c = 20 + 273 = 293 k

= final temperature = ?

using the equation