You set out to reproduce thomson’s e/m experiment with an accelerating potential of 150 v and adeflecting electric field of magnitude 6.0 ×106 n/c(a) at what fraction of the speed of light do the electrons move? (b) what magnetic-field magnitude will yield zero beam deflection? (c) with this magnetic field, how will the electron beam behave if you increase the acceleratingpotential above 150 v?

a. v' = 24.22 x 10 ⁻³

b. β = 0.825 T

Explanation:

V = 150 V , E = 6.0 x 10 ⁶ N / C

a.

¹/₂ * m * v² = e * V

v = √ 2 * e / m * V

v = √ 2 * 1.76 x 10 ¹¹ * 150 v  = √ 5.28 x 10 ¹³

v = 7.26 x 10 ⁶ m /s

v' / c = 7.26 x 10 ⁶ m /s  / 3.0 x 10 ⁸ = 24.22 x 10 ⁻³

b.  

β = E / V

β = 6.0 x 10 ⁶ / 7.266 x 10 ⁶

β = 0.825 T

c.

When the increasing the accelerating potential speed it doesn't change the up wired the electric force and the magnetic force the electron be beat down more .

answer: at 24 february, 2014 the population gets twice of its initial population.

explanation:

since we have given that

the population for alpha city, t years after january 1, 2004 is given as

first we find out the initial population, i.e. t=0,

so, our quadratic equation becomes,

according to question, we have said that if the population has twice its initial population, then it becomes

so, time taken to reach this above mentioned population is given by

now, we know that time can't be negative so, we take t=9.149 years.

hence, at 24 february, 2014 the population gets twice of its initial population.